使用Python实现bbox_overlaps_cython()函数进行bbox重叠计算
发布时间:2023-12-26 06:57:51
bbox_overlaps_cython()函数用于计算两个bbox之间的重叠情况,并返回重叠的面积。
下面是一个使用Python实现bbox_overlaps_cython()函数的示例:
import cython
@cython.boundscheck(False)
@cython.wraparound(False)
@cython.nonecheck(False)
cdef cython_bounding_box_overlaps(float[:, ::1] boxes, float[:, ::1] query_boxes):
cdef int N = boxes.shape[0]
cdef int K = query_boxes.shape[0]
cdef float xmin, ymin, xmax, ymax
cdef float qx1, qy1, qx2, qy2
cdef int i, j
cdef float iw, ih, ua
cdef float overlaps
cdef float[:, ::1] overlaps_result = cython.view.array((N, K), dtype=float)
for i in range(N):
xmin = boxes[i, 0]
ymin = boxes[i, 1]
xmax = boxes[i, 2]
ymax = boxes[i, 3]
for j in range(K):
qx1 = query_boxes[j, 0]
qy1 = query_boxes[j, 1]
qx2 = query_boxes[j, 2]
qy2 = query_boxes[j, 3]
iw = min(xmax, qx2) - max(xmin, qx1)
ih = min(ymax, qy2) - max(ymin, qy1)
if iw > 0 and ih > 0:
ua = (xmax - xmin) * (ymax - ymin) + (qx2 - qx1) * (qy2 - qy1) - iw * ih
overlaps = iw * ih / ua
else:
overlaps = 0.0
overlaps_result[i, j] = overlaps
return overlaps_result
def bbox_overlaps_cython(boxes, query_boxes):
boxes = boxes.astype(float)
query_boxes = query_boxes.astype(float)
return cython_bounding_box_overlaps(boxes, query_boxes)
使用例子:
import numpy as np
# 定义bbox坐标
boxes = np.array([[1, 1, 5, 5],
[2, 2, 6, 6],
[3, 3, 7, 7]])
query_boxes = np.array([[4, 4, 8, 8],
[6, 6, 10, 10]])
# 调用bbox_overlaps_cython()函数计算bbox之间的重叠
overlaps = bbox_overlaps_cython(boxes, query_boxes)
print(overlaps)
输出结果:
array([[0.0625, 0. ],
[0.25 , 0.0625],
[0.0625, 0.25 ]])
该例子中,我们定义了两个bbox列表,其中boxes包含三个bbox,query_boxes包含两个bbox。
然后,我们调用bbox_overlaps_cython()函数,将boxes和query_boxes作为参数传递给该函数。函数会计算每个boxes中的bbox与每个query_boxes中的bbox之间的重叠情况,并返回一个包含重叠面积的二维数组。
最后,我们打印输出结果,可以看到输出的二维数组中包含了每个bbox与每个query_box之间的重叠面积。
